Can anyone tell me what is the matter with the following code? Is it a problem with the code or with Windows Vista?

use strict;
use warnings;
use 5.010;

print 'Enter your password: ';

my $password = eval {
    local $SIG{ALRM} = sub {die "timeout\n"};
    alarm 5;
    return <STDIN>;
};

alarm 0;

if ($@ =~ /timeout/) {
    say "You timed out.";
}

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In reply to $SIG{ALRM} and windows vista? by 7stud

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