There appears to be an error in your code. 
$mp3 =~ s/\./\\\./g;

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inserts a backslash before the period in $mp3. But since $mp3 appears on the left side of a regexp that backslash will be a literal one. If $ARGV[0] includes a backslash, then inside the right-side of a regexp that backslash is a special character which merely turns the next character, but not the backslash itself, into a literal.

Thus, 

if ($mp3 =~ /$ARGV[0]/i){

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will always fail because anyfilename.mp3 will never appear in anyfilename\.mp3

Adding that backslash to $mp3 breaks the program.

In reply to Re: The right way to avoid an error by sierrathedog04
in thread The right way to avoid an error by diarmuid

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