say you want to match '99' in : 1990 , you can... $variable =~ /\d+(99)\d+/

will match the 99 in 1990, and store it in $1, because the regexp was put in the back reference using ()'s ie:

/\d+(\d+\d+)\d+/ will store the 2nd and 3rd digits in $1

$var =~ /hello\s+(.*)/ will store whatver is after hello in $1

if: $var = "hello world"; then $1="world";

In reply to Re: Reg ex question by Anonymous Monk
in thread Reg ex question by costas

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