That seems reasonable to me. There's always more than one way to do it.

Here's the more traditional version of yours:

for (0..$#a) {
   $a[$_] = $a[$_] . "-" . shift(@b);
}

[download]
Update: I see now I missed the redundant $_ assignment in the original node. Too bad whoever -- this didn't help me out with an explanation :)

In reply to Re: Combining Arrays by kschwab
in thread Combining Arrays by iamcal

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