If I understand your question... You want to perform a substitution on the value in $foo, without changing the value of $foo or copying the value to another variable first?

I think that you will be able to meet any two of those three requirements. :)

Here's something to consider, although it requires $foo to be a package variable rather than a lexical, and still involves copying the value:

$foo = "bar baz"; { (local $foo = $foo) =~ s/bar/quux/; # do something with the modified $foo } # now the original $foo is back again
BTW, there is nothing wrong with your use of my inside the parentheses.

In reply to Re: Substituting without modifying by chipmunk
in thread Substituting without modifying by crackhed

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