Your method works great using lexical variables as well, because the perl interpreter correctly interpolates the temporary value of $foo when that temporary value is in scope. 
use strict;
my $foo = "bar baz";
{
  (my $foo = $foo) =~ s/bar/quux/;
  # do something with the modified $foo
    $foo = "changed it";
    print "The temporary value of foo is $foo.\n";
}
# now the original $foo is back again
print "The original value of foo is $foo.\n";

[download]
Running under ActiveState 5.6.1 and Windows ME, the above code first returns the temporary value of "changed it" and then the original value of "bar baz".

In reply to Re: Re: Substituting without modifying by sierrathedog04
in thread Substituting without modifying by crackhed

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