I need to do the time difference as $date2-$date1
I'll assume you need the difference in seconds. If you need minutes or hours, divide by 60 or by 60/60.
I've used Date::Calc for a long time with fine results. There are several functions (as well as an OOP interface for the same functions) available, depending on what you need. You'll have to do a little parsing, but then you turn the string into the seconds since the epoch (doesn't matter which one) and just subtract one from the other.
use strict; use warnings; use Date::Calc qw(Mktime); # Turns a date string into seconds since ep +och my $dt_str2="31/12/2009 6:29:26 p.m."; my $dt_str1="31/12/2009 6:14:25 p.m."; my ($day, $mo, $yr, $hr, $min, $sec, $mer) = $dt_str1 =~ m{(\d+)/(\d+)/(\d+) (\d+):(\d+):(\d+) ([ap])}; $hr += 12 if $mer eq 'p'; die "Problem with date string $_" if $hr > 23; # Note element order for Date::Calc functions! my $dt1 = Mktime($yr, $mo, $day, $hr, $min, $sec); ($day, $mo, $yr, $hr, $min, $sec, $mer) = $dt_str2 =~ m{(\d+)/(\d+)/(\d+) (\d+):(\d+):(\d+) ([ap])}; $hr += 12 if $mer eq 'p'; die "Problem with date string $_" if $hr > 23; my $dt2 = Mktime($yr, $mo, $day, $hr, $min, $sec); print $dt2 - $dt1, "\n";
Or you could make it into a loop if you had a lot of these to parse at once (and it's cleaner looking too).
use strict; use warnings; use Date::Calc qw(Mktime); # Turns a date string into seconds since ep +och my $dt_str2="31/12/2009 6:29:26 p.m."; my $dt_str1="31/12/2009 6:14:25 p.m."; my @dates_to_compare; for ($dt_str1, $dt_str2) { my ($day, $mo, $yr, $hr, $min, $sec, $mer) = m{(\d+)/(\d+)/(\d+) (\d+):(\d+):(\d+) ([ap])}; $hr += 12 if $mer eq 'p'; die "Problem with date string $_" if $hr > 23; # Note element order for Date::Calc functi +ons! push @dates_to_compare, Mktime($yr, $mo, $day, $hr, $min, $sec); } # using pop clears out the array, which is helpful when looping print pop(@dates_to_compare) - pop(@dates_to_compare), "\n";
I hope this helps
marmotIn reply to Re: More Date Arithmetic/Manipulation: Question
by furry_marmot
in thread More Date Arithmetic/Manipulation: Question
by newbie01.perl
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