Well, I guess I deserved to lose an experience point for my hastily posted "solution" yesterday. In an effort to redeem myself, here is yet another solution to this problem: 

#!/usr/bin/perl -w reg.pl
my ($p, @q, $matchchar, $nummatch, $rep, $count, $q, $out);
$p = 'Terrence and Phillip are sweet';
$count = 0;
$matchchar = "e";
$nummatch = 3;
$repchar = "1";

@q = split (/(.*?)/, $p);
for($i = 0; $i < $#q + 1; $i++) {
    $_ = $q[$i];
    $count += 1 if (/$matchchar/);
    if (/$matchchar/ && ($count > $nummatch)) {
        $q[$i] = $repchar;
    }
}

$out = join ("", @q[0 .. $#q]);
print "out === $out";

[download]

This one works, and solves the correct problem.

sharle

In reply to Re: Replacing a given character starting with the xth occurence in a string by sharle
in thread Replacing a given character starting with the xth occurence in a string by Anonymous Monk

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