much more efficient would be to divide the coordinates length by the bin side and round that off and concatenate those together and they form a pretty good hash key(and you don't need to compute minimum or maximum any more). but here's a solution following your line of thought: 

use strict;
use warnings;
use List::AllUtils qw/minmax/;

my @points = (
[3.70722,0.54617,],
[3.67342,0.64892,],
[3.75017,0.85075,],
[3.82831,0.83506,],
[3.71852,0.79251,],
[3.80706,0.70426,],
[3.91839,0.94094,],
[3.90726,0.81722,],
[3.89007,0.76107,],
[3.98006,0.62477,],
);


my $bins;
my $binside = 0.1;

my ($xmin,$xmax) = minmax( map { $_->[0] } @points );
my ($ymin,$ymax) = minmax( map { $_->[1] } @points );

for(    my $xbin=$xmin ; $xbin<=$xmax ; $xbin+= $binside) {
    for(my $ybin=$ymin ; $ybin<=$ymax ; $ybin+= $binside) {
        my $p = $points[0];
        if(   $p->[0] >= $xbin && $p->[0] < $xbin + $binside &&
              $p->[1] >= $ybin && $p->[1] < $ybin + $binside ) {
                  $bins->{$xbin.$ybin} = [] 
                  unless($bins->{$xbin.$ybin});
                  push @{ $bins->{$xbin.$ybin} } , (shift @points);
          };
    }
}

print scalar(keys(%$bins));

4

[download]
this sounds a lot like the bin packing problem.

In reply to Re: 2D binning by spx2
in thread 2D binning by austinby

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