Sorry I disagree that this is a good example - "by the book" - of a closure, because it's far to magic.
Each closure has a new instance of $i which is mutable, looking at the code I would expect either always the same instance of $i or $i being an alias of an immutable literal... but it's neither of these...
for my $i (1..3) {
$numbers{$i} = sub { $i++;print $i };
}
UPDATE:
OK my problem derived from the difference between range operator and comma operator in producing lists:
DB<37> for my $i (1,2,3) { $numbers{$i} = sub { $i++;print $i }; pri
+nt \$i}
SCALAR(0x9338210)SCALAR(0x92bdc90)SCALAR(0x9338190)
DB<38> &{$numbers{1}}
Modification of a read-only value attempted at (eval 43)[/usr/share/pe
+rl/5.10/perl5db.pl:638] line 2.
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