uint8 i = 2; uint16 j = i; Does the second assignment change the meaning of 2?
Cheap theatrics. Cos now int i = -1; uint j = i; it does.
Presumably you mean "anything else that might cause perl to use the 32/64-bit string format",
Nope! I meant exactly what I said.
Paraphrase: If I populate the PV of a perl scalar with byte values, and later call SvPVX() to gain access to those byte values, I will get back exactly what I put in them...unless in the interim, I explicitly do something to change them. No presumptions or assumptions. Simply fact.
And using SvPVX() will NEVER cause it to
silently encode your bytes using UTF-8.
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
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