Cheap theatrics. Cos now int i = -1; uint j = i; it does.

I never said or implied that the types are equivalent. Different types have different range, precision and costs.

32/64-bit strings have a wider range, but they are more costly in every respect. (That's why we have 8-bit strings at all.) The range of 32/64-bit strings encompasses the range of 8-bit strings, so your signed vs unsigned analogy is broken.

Nope! I meant exactly what I said.

If you meant what you said, you haven't ruled out doing something like $pascal_bytes = chr(length($bytes)) . $bytes;. For long enough strings, it upgrades without calling upgrade and without Perl assigning any meaning to the string.

In reply to Re^24: Interleaving bytes in a string quickly by ikegami
in thread Interleaving bytes in a string quickly by BrowserUk

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