<merlyn>First, I point you to an article I wrote.</merlyn>

Basically, doing *alias = \$name makes $alias and $name the same thing. Thus, doing *alias = \*name is making all things with a symbol name 'alias' the same thing as those with the name 'name' (in some specific package, let's say main::).

The wonderful thing about globs is that they can be used where references are expected: @{ *foo } is like @{ \@foo }. Thus, you can use a glob where you would ordinarily use a reference to a glob. That means that you can say *alias = *name instead of *alias = \*name.

Another reason that *alias = *name works the same way as *alias = \*name is because you can assign a string to a typeglob:

*foo = "bar"; print *foo; # *main::bar *foo = "this::that"; print *foo; # *this::that
So, since a glob in scalar context is its "name", you can assign that name to a glob.

P.S. You can't say \*alias = ..., since you can't assign to a reference of something (that's why \$foo = \$bar doesn't work).

japhy -- Perl and Regex Hacker


In reply to Re: Taken out of Context by japhy
in thread Taken out of Context by Petruchio

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