$ perl -le 'print scalar(localtime(20100302165019));'
Mon Mar 22 05:03:39 638923
        ^^          ^^^^^^

[download]

(with a 64-bit Perl)

The string '20100302165019' doesn't represent seconds since "the epoch", which is what localtime() would expect.

In reply to Re^3: Date conversion in perl? by almut
in thread Date conversion in perl? by Anonymous Monk

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