-p + <>???
-p + print???
Your code should be
perl -e"@lines=<>; print @lines[41900..50000];" data02.log > data03.lo +g
As for your question,
perl -ne"next if $.<41901; print; exit if $.==50001;" data02.log > dat +a03.log
($. is one-based while arrays are zero-based. That's why I changed the indexes by one.)
In reply to Re: Print some lines in a range
by ikegami
in thread Print some lines in a range
by ranrodrig
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