Perl

my $z;
my $x = sub { $z = 2 + 2 } ;

eval $x;  # doesnt run the sub routine!

$x->(); # oh, you mean I have to do THIS to 
             #eval THIS, but I use eval to eval 
              # other things. not so consistent

print $z;

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Scheme/Lisp


(setq closure (delay (setq z (+ 2 2))))
(eval closure) ;;; works

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In reply to Lisp is More Evaluatable by princepawn

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