Think of the following: a solution to the 0-1 knapsack problem can be easily generalized to the bounded case, you just have to explicitly list the items with nr>1. Think of my previous example as this (just written abbreviated there): 
w    v    v/w
3  3.1  31/30 # case a
2    2      1 # case b (together with the following line)
2    2      1 # case b

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In reply to Re^4: knapsack problem solved by regex by rubasov
in thread knapsack problem solved by regex by rubasov

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