Ok, so you say the coercion that occurs is from list to array. If that's true, then
my @a = @b;
also does coercion (array to list, then list to array), and the topic becomes irrelevant and silly. It may be true, but the concept is completely useless and not worth discussing

I think the main issue is that we're talking about different levels: When I look at Perl code, I don't see that my @a = @b does a coercion to list and back again - so to me it doesn't happen. You seem to know that either by knowing the core or by memorizing some rules that are not obvious from looking at Perl code, or the documentation in perlsyn et al.

So to me the isomorphism of a list of a single scalar and a list containing a single scalar also does not exist - When I see $foo, I think "this is a scalar" and not "this is a scalar, also constituting a list of a single scalar". It's the assignment that turns the RHS of my @a = $b into a list, and that's what I call coercion.

Perl 6 - links to (nearly) everything that is Perl 6.

In reply to Re^7: compiling perl scripts aka why is perl not as fast as C by moritz
in thread compiling perl scripts aka why is perl not as fast as C by punkish

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