I am looking for an efficient Perl way to replace the following bash command or MySQL statement

 bash:
    date -d"1899-12-30 +40254 days"

 MySQL:
    DATE_ADD('1899-12-30', interval 40254 day)

[download]

Both export '2010-03-17'. I need to find a reliable and efficient Perl way or a small neat Perl module to handle the same thing, any recommendations?

Thank in advance

lihao

Update: Thanks guys for all suggestions. I am actually looking for some lighter solution or new Perl modules which I don't know. the target is to transfer the parsed Excel datetime into MySQL datetime format. In some 32-bit Linux box, i.e. 32bit RHEL5, the -d switch on the date command does NOT work for all datetime. Since I only care about the exact date instead of time, I am using the following formula to handle the date transfer(where 2209143600 is the second from "1899-12-30 00:00:00" on local to "1970-01-01 00:00:00" by a bash line date -d '1899-12-30 00:00:00' +%s)

sub get_excel_date
{
    return if not $_[0];
    my $date = shift;
    my @x = localtime($date*24*3600 - 2209143600);
    return sprintf("%04d-%02d-%02d", $x[5]+1900, $x[4]+1, $x[3]);
}

[download]

In reply to Looking for an efficient way to do datetime transfer by lihao

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