Sure, with the /e modifier: $str =~ s/_(.*?)_/test($1)/eg;

See perlop for details. Also note that $1 should be used instead of \1 in the substitution part of a regex.

Update: oops, missed the actual /e in the example - bellaire++

Perl 6 - links to (nearly) everything that is Perl 6.

In reply to Re: Call subroutines inside regexp, using backrefences as parameters by moritz
in thread Call subroutines inside regexp, using backrefences as parameters by Anonymous Monk

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