And then there's the issue that the output you are expecting is from a sh builtin (not the external command from my first post), but you didn't ensure that sh is executed to interpret the command. 
my $time = `/bin/sh -c 'time ...'`;

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In reply to Re: Time command output is not stored into the variable. by ikegami
in thread Time command output is not stored into the variable. by ungalnanban

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