bar is still visible outside of foo, so make it lexical 
sub foo {

  my $bar =     sub {
        my ($i) = @_;

        push @arrb, $arra[$i];
        
  };

  $bar->($#arra);

  ...
}

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In reply to Re: a sub within a sub -- revisiting by Anonymous Monk
in thread a sub within a sub -- revisiting by punkish

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