it costs nothing because a (positive) signed N-bit integer will always fit in an unsigned N-bit integer regardless and mean the same thing.

It does cost something: You have to add (size_t) everywhere. The question was about what's gained.

In reply to Re^11: [OT] LLP64 .v. LP64 portability by ikegami
in thread [OT] LLP64 .v. LP64 portability by BrowserUk

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