Yes, that does work. What does not work so easily is when you want to pass the values of a hash to the function in such a way that it can write them. Eg. this works, the function can change the value in the hash: 

my %d = ("foo", "bar"); sub fs { $_[0] = "quux"; } fs(values %d); prin
+t join(" ", %d), $/;
# OUTPUT: foo quux

[download]

But this does not work: 

my %d = ("foo", "bar"); sub fi { ${$_[0]}[0] = "quux"; } fi([values %d
+]); print join(" ", %d), $/;
# OUTPUT: foo bar

[download]

Instead you could do 

my %d = ("foo", "bar"); sub fi { ${$_[0]}[0] = "quux"; } sub capture {
+ \@_ } fi(capture(values %d)); print join(" ", %d), $/;
# OUTPUT: foo quux

[download]

But that's probably all irrelevant to your question.

In reply to Re: passing array ref without variable by ambrus
in thread passing array ref without variable by vit

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