The problem is you're trying to iterate over an array that you're changing. You enter your loop and set $x to 1 (which occupies index 0). You then shift '1' out and lower the indices of all remaining elements. When you hit the beginning of the loop again, $x is set to 3 because it's now in index 1. You then shift 2 out and your loop exits because there's nothing at index 2 (or index 1 for that matter).
If you're trying to empty the array, you could try:
my @arr = ( 1, 2, 3 ); for my $x ( shift @arr ) { #do some stuff }
Edit: What the hell was I thinking when I wrote that? I meant to write the while loop that BrowserUk wrote below. Please do not use my answer. It doesn't work.
In reply to Re: Why does a full iteration over array & shift is not emptying the array
by AR
in thread Why does a full iteration over array & shift is not emptying the array
by Anonymous Monk
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |