So which solution do you expect with this data? 
A C
B C

[download]

There is no path from A to B, so do you consider them in the same or different groups?

Or do you have a guaranty that these intersections are not possible?

Cheers Rolf

In reply to Re: Finding all connected nodes in an all-against-all comparison by LanX
in thread Finding all connected nodes in an all-against-all comparison by Anonymous Monk

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