Adding:

C12 Contig11 C12 Contig5

to the test data prints:

Group 1 : Contig6 Contig7 Group 2 : C12 Contig3 Contig4 Contig5 Contig8 Contig9 Contig10 Contig1 +1 Group 3 : C12 Contig1 Contig2 Contig3 Contig4 Contig5 Contig8 Contig9 +Contig10 Contig11

where something like:

Group 1 : Contig6 Contig7 Group 2 : C12 Contig1 Contig2 Contig3 Contig4 Contig5 Contig8 Contig9 +Contig10 Contig11

is expected, at least according to my understanding of the OP's 'connected by at least one edge (including non-reciprocal edges)' criteria.

True laziness is hard work

In reply to Re^2: Finding all connected nodes in an all-against-all comparison by GrandFather
in thread Finding all connected nodes in an all-against-all comparison by Anonymous Monk

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