Try print $ARGV[0].

Addendum:

Extracted from perlvar 

@ARGV

The array @ARGV contains the command-line arguments intended for the s
+cript. $#ARGV is generally the number of arguments minus one, because
+ $ARGV[0] is the first argument, not the program's command name itsel
+f. See $0 for the command name.

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In reply to Re: query about perl by linuxer
in thread query about perl by yogesh536

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