Your code makes no sense:
$retVal = $someObject->bar()->doSomething();
$retVal = \$retVal;
You overwrite $retVal immediately. Maybe you meant:
my $myVal = $someObject->bar()->doSomething();
$retVal = \$myVal;
Log4perl->debug('retval: ', sub {$retVal});
return $retVal;
Then, I think you won't have a memory leak, as the only thing that's keeping $myVal alive is the reference in $retVal. When that reference goes out of scope, also $myVal will get released.
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