"The /o option means that the regexp is interpolated and compiled only once for the complete life of the program."

But why then is main::CORE:regcomp still being called on every iteration, just as in the cases without /o?

In reply to Re^2: Regexp optimization - /o option better than precompiled regexp? by Anonymous Monk
in thread Regexp optimization - /o option better than precompiled regexp? by Hessu

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