Hi monks,

I received a binary string on twitter, and I translated it into words in perl: 

my $string="01100110 01100101 01100101 01101100 01101001 01101110 0110
+0111 00100000 01101100";

#$string=~ s/ (\d+)/pack('B8', $1)/egx; # way 1
$string=~ s/ (\d+)/chr(oct('0b'.$1))/egx;  # way 2

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My question is why perl do not support 
chr('0b'.$1) #it will throw a error message: Argument "0b01100110 " is
+n't numeric

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Thanks very much!

UPDATE:

I mean, I know I should pass a number to chr, but is there a way to convert a string to number explicitly like perl6? 
+('0b'~'0111011')          #perl6

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I am trying to improve my English skills, if you see a mistake please feel free to reply or /msg me a correction

In reply to what is difference between chr and oct? by xiaoyafeng

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