that's the question i was raised here. How to modify the regular expression to find consecutive 5 words which the center word has year. if i use some thing like below 

#$var=~s/(\w?) (\w?) ([0-9]{4}+[a-zA-Z]?) (\w?) (\w?)/&identify_year($
+1.$2.$3.$4.$5)/ge;

[download]

it's not giving my required output and it fails here. "b1990 and 2000." U.S. etc., if u try. read my all questions clearly the year can occurs in any format not only 4 digits.

In reply to Re^4: find one by one occurances by Selvakumar
in thread find one by one occurances by Selvakumar

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