Well if you just use the idea that choosing 2 people out of a group has a certain number of possibilities, it would stand to reason when the possibilities get larger than 366, you are probably going to have two people with the same birthday. If you choose two people out of a group of 28 people, there are 378 ways to do this without repeats! That makes the odds pretty good that two of them with have the same birthday.

In reply to Re^2: Birthday Chances by Anonymous Monk
in thread Birthday Chances by YuckFoo

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