B::Deparse reveals all:

$ perl -MO=Deparse
package foo;

sub ARGV { print "in foo::ARGV\n" }

package main;

foo->ARGV;

package foo;
sub main::ARGV {
    print "in foo::ARGV\n";
}
package main;
'foo'->ARGV;
- syntax OK

[download]

I haven't yet found the part of the parser which forces sub ARGV into main::.

In reply to Re: ARGV as a sub name? by chromatic
in thread ARGV as a sub name? by perl5ever

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