Ok, so,

sub foo($x, $y) { say $x ~ $y };
my $foo_ref = &foo;

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assigns a reference to $foo_ref (makes sense (since I don't see why I'd want to copy a function), and

my @bar = <a b c>;
my $bar_ref = @bar;   # Assigns a reference. Ok.
my $bar_ref2 := @bar  # Same as above? XXX
my @bar_copy = @bar;  # Makes a copy of @bar. As expected.

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and

my $qux = SomeClass.new;  # $qux is a reference to an object
my $qux_ref = $qux;       # makes a copy of the reference (?)

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Does that copy the object referred to by $qux, or just the reference?

However,

my $xyz = 'hi';
my $xyz_ref = $xyz;  # not a ref!

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copies $xyz as expected. Correct?

In reply to Re^8: Reference in Perl 6 by Anonymous Monk
in thread Reference in Perl 6 by Anonymous Monk

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