I have two programs. The first program creates a log file, same as display of the terminal. So I am using the below code in unix terminal, for get the log file creation. And it’s working fine.
# first.pl open (STDOUT, "| tee -a $LOGFILE") or die "Teeing off: $!\n";
At the end of the program I call the second program (`perl second.pl $LOGFILE`) and I wish to get the user entered inputs only in $LOGFILE. ( No need to captured the terminal display). I am using the LOG file handler to append the user entered inputs. But I am getting the terminal display also. How to avid the terminal display in the log file.
Thanks,
Mani Muthu
Hi Monks
I got the solution. Below I place the sample code for that one.
The first file : I wish to captured the screen display in log file
# parent.pl # Preserve the filehandler open(OLDOUT, ">&STDOUT"); $LOGFILE="output.txt"; open LOG_FH, ">>$LOGFILE" ; # disable perl buffering so that when you log messages on the screen t +o the logfile , select LOG_FH; $| = 1; select STDOUT; $| = 1; # Open STDOUT to log messages to file ... open (STDOUT, "| tee -a $LOGFILE") or die "Teeing off: $!\n"; print "\nEnter Parent Process Input : "; $p_input1=<>; chomp ($p_input1); print LOG_FH "\nYou Entered : $p_input1"; close (LOG_FH); close (STDOUT); ## redirect the file handler open(STDOUT, ">&OLDOUT"); ## No need the screen output to the log file system("perl child.pl $LOGFILE");
The second file : I wish to user entered inputs only in the log file
# child.pl $LOGFILE=$ARGV[0]; open FOUT, ">>$LOGFILE" ; print "\nEnter the child process input : "; $c_input1=<STDIN>; print FOUT "\nYou Entered Child Input : $c_input1"; close (FOUT);
In reply to Terminal Display - Log File Creation by k_manimuthu
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