local doesn't remove the magic — the variable is still tied in the block — so
is roughly the same as{ local $tied = 'x'; ... }
{ my $restorer = localiser($tied, 'x'); ... }
given a function that creates an object that restores $tied on destruction.
use Sub::ScopeFinalizer qw( scope_finalizer ); sub localiser { my $var_ref = \$_[0]; my $saved = $$var_ref; $$var_ref = $_[1]; return scope_finalizer { $$var_ref = $saved }; }
(Sub::ScopeFinalizer is trivial to re-implement.)
Demonstration:
use strict; use warnings; use Sub::ScopeFinalizer qw( scope_finalizer ); { package Tied; use Tie::Scalar; our @ISA = qw( Tie::StdScalar ); sub FETCH { return ${ $_[0] }++ } } sub localiser { my $var_ref = \$_[0]; my $saved = $$var_ref; $$var_ref = $_[1]; return scope_finalizer { $$var_ref = $saved }; } { tie our $tied_pkg, 'Tied'; $tied_pkg = 'a'; print $tied_pkg; # a { local $tied_pkg = 'x'; print $tied_pkg; # x print $tied_pkg; # y print $tied_pkg; # z } print $tied_pkg; # b print $tied_pkg; # c print "\n"; } { tie my $tied_lex, 'Tied'; $tied_lex = 'a'; print $tied_lex; # a { my $restorer = localiser($tied_lex, 'x'); print $tied_lex; # x print $tied_lex; # y print $tied_lex; # z } print $tied_lex; # b print $tied_lex; # c print "\n"; }
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In reply to Re: localizing lexical without messing with tie ?
by ikegami
in thread localizing lexical without messing with tie ?
by LanX
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