It's got nothing to do with operand evaluation order. It has to do with pre-increment returning lvalues.
f(++$i, ++$i)
is more or less equivalent to
do {
local @_;
alias $_[0] = ++$i;
alias $_[1] = ++$i;
&f;
}
Since the pre-increment operator returns the variable itself and not a copy, the above is the equivalent to
do {
local @_;
++$i; alias $_[0] = $i;
++$i; alias $_[1] = $i;
&f;
}
As you see, f() sees the same value for both arguments as both arguments are the same variable.
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