Apologies. I meant to convey that $1 would "return" "\n" as well, instead of the non-spaces before it.
The regex I'd be using is DIP\s+\S+\s+(\S+).*?\\n

In reply to Re^2: Regex: Ignore \n in \S by manav_gupta
in thread Regex: Ignore \n in \S by manav_gupta

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