Because I know something by another name

That doesn't wash either.

  1. In this: f( 1 , 2 );, The constants 1 & 2 are the operands of the comma operator.
  2. But in this: f( 1+2 , 3+4 ),

    the operands of the comma operator are the results of the subexpressions: 1+2 and 3+4.

    Ie. The operands of the comma operator are the values 3 & 7.

By analogy, in this: f( ++$n , ++$n ), the operands of the comma operator should be the results of the preincrement subexpressions.

Not two references to $n after both sub-expressions have been evaluated.

As for your ploy of resorting to meta-argument to distract from the argument, I'm going to ignore it this time, just like I did last time. And the time before...


Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
RIP an inspiration; A true Folk's Guy

In reply to Re^7: Pre vs Post Incrementing variables by BrowserUk
in thread Pre vs Post Incrementing variables by SavannahLion

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