By analogy, in this: f( ++$n , ++$n ), the operands of the comma operator should be the results of the preincrement subexpressions.
By the same logic in f($n) f should be passed the result (value) of $n, disallowing f from modifying $n.

Perl doesn't work that way.

In reply to Re^8: Pre vs Post Incrementing variables by JavaFan
in thread Pre vs Post Incrementing variables by SavannahLion

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