It's creating a lexical variable $x, and taking a reference of it. Now the name disappears when exiting the block, but since $singleton holds a reference, the value (which in this case is undefined) can still be gotten.

Note that all you need to create an object is a reference. You don't need a reference to a "large" structure like a hash or an array. Any reference will do - including one to a scalar.

In reply to Re: syntax question by JavaFan
in thread syntax question by Anonymous Monk

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