Dear offerers of Perl Wisdom I have data with the following output 

 
itemid  FROM_UNIXTIME(clock)       value
26603   2010-10-09 00:00:23     38784360.8136
26603   2010-10-09 00:01:23     36529742.6667
26603   2010-10-09 00:02:23     36966880.8000
26603   2010-10-09 00:03:23     35666405.8667
26603   2010-10-09 01:05:23     35600190.6667
26603   2010-10-09 02:06:23     39175029.2000
26603   2010-10-09 03:07:23     35386478.4000
26603   2010-10-09 04:08:27     35773482.7500
26603   2010-10-09 05:09:23     39073367.5714
26603   2010-10-09 06:10:23     34379049.8667
26603   2010-10-09 07:11:24     33984045.7705
26603   2010-10-09 09:12:23     36276301.8305
26603   2010-10-09 10:13:23     37248366.0000
up to time 23:59
26603   2010-10-09 23:59:23     39393421.3333

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What I'm trying to do is count the number of readings/occurrences for each hour and divide that value to the sum of values for that hour. I've so far been only able to get the occurrences for each hour with the following code

#!/usr/bin/perl
        my $count={};
        while (<>) {
                chop;
                @F = split;
                @J=split(/\:/,$F[2]);
                if ( $J[0] =~ /[0-9][0-9]/ ){ $count{$J[0]}++};
        }
        foreach $key(sort(keys(%count))){
            print "$key\t$count{$key}\n";
        }

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But I'm not able to get the hourly sum for each hour, I've tried different things like util sum and other code. If anyone can suggest a better way of summing up values based on hours I'll be really grateful

In reply to Calculate hourly averages by addyrocker

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