Is this more what you were thinking of?

#!/usr/bin/perl use warnings; use strict; my %hours; while(<DATA>) { next unless $_ =~ /\w+/; my @F = split; if ( $F[2] =~ /(\d{2})\:\d{2}:\d{2}/ ) { $hours{$1}{value} += $F[3]; $hours{$1}{count}++; } } for ( sort { $a <=> $b } keys %hours ) { print "Sum at $_ hours is ", $hours{$_}{value}, "\n"; print "Count at $_ hours is ", $hours{$_}{count}, "\n"; } __DATA__ 26603 2010-10-09 00:00:23 38784360.8136 26603 2010-10-09 00:01:23 36529742.6667 26603 2010-10-09 00:02:23 36966880.8000 26603 2010-10-09 00:03:23 35666405.8667 26603 2010-10-09 01:05:23 35600190.6667 26603 2010-10-09 02:06:23 39175029.2000 26603 2010-10-09 03:07:23 35386478.4000 26603 2010-10-09 04:08:27 35773482.7500 26603 2010-10-09 05:09:23 39073367.5714 26603 2010-10-09 06:10:23 34379049.8667 26603 2010-10-09 07:11:24 33984045.7705 26603 2010-10-09 09:12:23 36276301.8305 26603 2010-10-09 10:13:23 37248366.0000
which yields the results:

C:\Code>perl values_per_hour.pl Sum at 00 hours is 147947390.147 Count at 00 hours is 4 Sum at 01 hours is 35600190.6667 Count at 01 hours is 1 Sum at 02 hours is 39175029.2 Count at 02 hours is 1 Sum at 03 hours is 35386478.4 Count at 03 hours is 1 Sum at 04 hours is 35773482.75 Count at 04 hours is 1 Sum at 05 hours is 39073367.5714 Count at 05 hours is 1 Sum at 06 hours is 34379049.8667 Count at 06 hours is 1 Sum at 07 hours is 33984045.7705 Count at 07 hours is 1 Sum at 09 hours is 36276301.8305 Count at 09 hours is 1 Sum at 10 hours is 37248366 Count at 10 hours is 1 C:\Code>

In reply to Re: Calculate hourly averages by dwm042
in thread Calculate hourly averages by addyrocker

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