I have an XS routine that (simplified) looks like this:
foo *
routine(a, b, c=NULL)
char *a;
int b;
bar_t * c;
CODE:
RETVAL = croutine( a, b, (c && SvOK(ST(2)) ) ?
c : cdefault );
OUTPUT: RETVAL
From perl, we can say
my $c = $objref;
routine( $a, $b, $c);
or
routine( $a, $b);
BUT, if we say:
my $c;
$c = $objref if( false );
routine( $a, $b, $c );
We fail with "c is not a reference" at runtime, when the interface code sees that c is not a reference.
This is because $c contains undef. But I'm prepared to supply another value in this case. (Note the SvOK(ST(2))).
How do I tell XS that a reference OR undef is OK for a parameter (c)?
Many thanks,
This communication may not represent my employer's views,
if any, on the matters discussed.
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