In my opinion, you're abusing the "given/when" construct. Yes, it works, because you have a boolean expression in the when() clauses. But you could put anything in the given part, and it would work just the same.
The point of "given/when", is that the value in the given clause is assigned to $_, and then you can use invisible default $_ in all the when() tests. From "perldoc perlsyn":
given($_) { when (/^abc/) { $abc = 1; } when (/^def/) { $def = 1; } when (/^xyz/) { $xyz = 1; } default { $nothing = 1; } } # and similarly given($foo) { when (undef) { say '$foo is undefined'; } when ("foo") { say '$foo is the string "foo"'; } when ([1,3,5,7,9]) { say '$foo is an odd digit'; continue; # Fall through } when ($_ < 100) { say '$foo is numerically less than 100'; } when (\&complicated_check) { say 'a complicated check for $foo is true'; } default { die q(I don't know what to do with $foo); } }
As far as I can see, you're using a given/when block to produce an if/elsif block with an extra level of indentation.
If you modify your foo/bar/baz example so that each print block has a new statement after it: pritn "\$_ is $_.\n";. That will print out what the value of $_ is, no matter which path you take. You will see that $_ is 'baz'. Your ($foo, $bar, $baz) evaluates the sequence of expressions and uses the last one as the chosen value. The earlier ones are evaluated only for their side-effect. Of course, $foo does not have a side-effect, but it could equally be $foo++, or $foo->(). That's why you're getting the message about "useless use of a private variable", because only the last one gets assigned to $_.
As Occam said: Entia non sunt multiplicanda praeter necessitatem.
In reply to Re^3: Text Analysis: given(){when(){}} block throws a 'useless use of private variable...etc' error
by TomDLux
in thread Text Analysis: given(){when(){}} block throws a 'useless use of private variable...etc' error
by biohisham
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