x = x + 1, which you've already said isn't safe

I never said that. I never implied that. For a start, what is "x"? It's not a perl variable is it. So it's just a meaningless equation.

Do I need to demonstrate further,

Yes. You need to demonstrate an actual segfault.

Why. Because what you are suggesting is possible, is IMPOSSIBLE. IT CANNOT HAPPEN.

Which makes your unfounded speculation: FUD. And, given that it is coming from you, a usually reliable and knowledgeable source, makes it dangerous and significant FUD. Possibly even deliberately malicious FUD.

So please, demonstrate your good intent by either:

  1. demonstrating a segfault using one of your original three perl statements.
  2. withdrawing the FUD.
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
RIP an inspiration; A true Folk's Guy

In reply to Re^6: is ||= threadsafe? by BrowserUk
in thread is ||= threadsafe? by perl-diddler

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