Hello!
I want to write a file if grep finds a certain pattern "error" in file c:/temp/logbook.log.
I thought i could use the returncode "0", could you help me where to place the "if" construct, my code is broken: 

use strict;
use warnings;
open (my $IN,"<c:/temp/logbook.log") || die "can not open datei: $!";
print grep /error/i, <$IN>;
if ($_ ==0){
my $file = '/temp/ok.txt';

#
   open FILE, '>', $file or die "Kann Datei $file nicht zum Schreiben 
+oeffnen: $!\n";
#
    print FILE "ok!\n";           
#
    close FILE;
}
close $IN;

[download]

Thanks
MH

In reply to Write a file if grep finds a pattern? by matze77

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