Hi

I need a perl reg-expression which extracts the pattern as below.

Basically we want to parse and extract the rpms from the packages.xml inside RHEL cd hence looking for a pattern which extracts the contents between >xyz</rpm>.

Note there might be any set of character/white space before > symbol but all the lines ends with </rpm> pattern.

Any help with regard to this is of great help.

Eg: 
 
        <rpm>acl-2.2.39-3.el5.x86_64.rpm</rpm>
        <rpm>acpid-1.0.4-9.el5_4.2.x86_64.rpm</rpm>
        <rpm>attr-2.4.32-1.1.x86_64.rpm</rpm>
        <rpm>audispd-plugins-1.7.13-2.el5.x86_64.rpm</rpm>
        <rpm>audit-1.7.13-2.el5.x86_64.rpm</rpm>
        <rpm>audit-libs-python-1.7.13-2.el5.x86_64.rpm</rpm>
        <rpm>basesystem-8.0-5.1.1.noarch.rpm</rpm>
        <rpm>libtermcap-2.0.8-46.1.x86_64.rpm</rpm>
        <rpm>bash-3.2-21.el5.x86_64.rpm</rpm>

        <rpm component="pamperuser04_rhel52_32" package="pam-per-user-
+0.4">pam_per_user-0.4-2053.vmw.i686.rpm</rpm>
        <rpm component="libusb0112_rhel52_32" package="libusb-0.1.12">
+libusb-0.1.12-5.1.2053.vmw.i686.rpm</rpm>
        <rpm component="usbutils071_rhel52_32" package="usbutils-0.71"
+>usbutils-0.71-2.1.2073.vmw.i686.rpm</rpm>
        <rpm component="libidn065_rhel52_32" package="libidn-0.6.5">li
+bidn-0.6.5-1.1.2053.vmw.i686.rpm</rpm>

[download]

Thanks in advance

asab

In reply to Search pattern from end of line by asab

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