The output of your program is 
Beginning is <I have >,number is <2>.

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The ".*+?" matches non greedily(Because of the ?), so the next "\d+" matches the first digit(s) it encounters, which is "2".

This means that the first expression (.*+?) gets everything before the "2".

     Syntactic sugar causes cancer of the semicolon.        --Alan Perlis

In reply to Re^3: What is the output for this ?? by NetWallah
in thread What is the output for this ?? by sreenath

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